Data Analysis is the process of collecting, organising, examining, comparing and interpreting numerical or categorical information to obtain meaningful conclusions.
Data analysis means converting raw data into useful information by using calculations, comparisons, ratios, percentages, averages and other statistical methods.
Data may be presented through tables, bar graphs, line graphs, pie charts, schedules or statements. In competitive examinations, questions generally require calculations based on the information given.
| Type | Meaning | Example |
|---|---|---|
| Qualitative | Describes qualities or categories. | Gender, colour, category |
| Quantitative | Expressed numerically. | Income, marks, population |
| Discrete | Countable numerical values. | Number of students |
| Continuous | Can take values within an interval. | Height, weight, temperature |
- Finding totals.
- Finding averages.
- Finding percentages.
- Finding ratios.
- Finding differences.
- Finding percentage increase or decrease.
- Comparing two or more data sets.
- Finding missing values.
- Finding maximum and minimum values.
Total = 400 + 500 + 600 + 700 + 800
= ₹3,000
Average = 3000/5
= ₹600
Percentage = 320/800 × 100
= 40%
A ratio compares two quantities of the same type.
Ratio = 60 : 45
= 4 : 3
Difference = 8700 − 7500
= 1,200 units
Increase = 650 − 500 = 150
Percentage Increase = 150/500 × 100
= 30%
Decrease = 80,000 − 68,000
= ₹12,000
Percentage Decrease = 12,000/80,000 × 100
= 15%
Growth Rate = 30,000/2,00,000 × 100
= 15%
When observations have different weights, use weighted average.
Here x represents the value and w represents its weight.
Σwx = 20×2 + 30×3 + 40×5
= 40 + 90 + 200
= 330
Σw = 2 + 3 + 5 = 10
Weighted Average = 330/10
= 33
Frequency tells us how many times a particular value occurs.
x = 10, 20, 30
f = 2, 3, 5
Σf = 10
Σfx = 10×2 + 20×3 + 30×5
= 230
Mean = 230/10
= 23
Salary Share = 2.5/10 × 100
= 25%
The denominator depends on the wording of the question. If the question asks percentage increase from A to B, A is the base.
Missing-value questions can often be solved using the known total, average or percentage.
Total = 42 × 5 = 210
Sum of known values = 35 + 40 + 45 + 50 = 170
Missing value = 210 − 170
= 40
If two quantities are in the ratio a:b and their total is T:
Second Quantity = b/(a+b) × T
Boys = 3/5 × 500 = 300
Girls = 2/5 × 500 = 200
| Quantity | Year 1 | Year 2 | Difference |
|---|---|---|---|
| Production | 5,000 | 6,000 | 1,000 |
| Sales | 4,000 | 5,200 | 1,200 |
| Profit | 800 | 1,000 | 200 |
| Concept | Formula |
|---|---|
| Total | Σx |
| Average | Σx/n |
| Frequency Total | Σf |
| Frequency Mean | Σfx/Σf |
| Weighted Mean | Σwx/Σw |
| Percentage | Part/Total × 100 |
| Percentage Increase | Increase/Original × 100 |
| Percentage Decrease | Decrease/Original × 100 |
| Growth Rate | (New−Old)/Old × 100 |
| Ratio | First : Second |
| Ratio Share | a/(a+b) × Total |
| Relative Frequency | f/Σf |
- The sales of a company for three years are ₹20 lakh, ₹25 lakh and ₹30 lakh. Find the total sales. ```
- The marks of five students are 60, 70, 80, 90 and 100. Find the average.
- A town has 50,000 people, of whom 32,500 are adults. Find the percentage of adults.
- Production rises from 4,000 units to 5,000 units. Find the percentage increase.
- Sales fall from ₹90,000 to ₹72,000. Find the percentage decrease.
- The ratio of male to female employees is 5:3. If there are 640 employees, find the number of males and females.
- The values 10, 20 and 30 have frequencies 3, 4 and 3. Find the arithmetic mean.
- Total expenditure is ₹12 lakh and expenditure on salaries is ₹3 lakh. Find the salary percentage.
- The average of six numbers is 35. Five numbers are 20, 30, 35, 40 and 45. Find the sixth number.
- A company's output increases from 80,000 units to 92,000 units. Find the growth rate. ```
| No. | Answer | No. | Answer |
|---|---|---|---|
| 1 | ₹75 lakh | 6 | 400 males, 240 females |
| 2 | 80 | 7 | 20 |
| 3 | 65% | 8 | 25% |
| 4 | 25% | 9 | 40 |
| 5 | 20% | 10 | 15% |