Problems on Races are based mainly on the relationship between distance, speed and time. Two or more persons run over the same or different distances, and we compare their speeds or finishing times.
Time = Distance ÷ Speed
Distance = Speed × Time
If A beats B by x metres in a race of D metres, then when A finishes the race, B has covered only D − x metres.
A : B = 100 : (100 − 20)
= 100 : 80
= 5 : 4
If the speed ratio of A and B is known, and A completes a race of D metres, the distance covered by B in the same time can be found directly from the speed ratio.
If speed ratio = a : b,
distance ratio in the same time = a : b
Distance ratio = 5 : 4
B's distance = 500 × 4/5
= 400 m
Therefore, A beats B by 100 m.
For the same race distance, time is inversely proportional to speed.
Time Ratio = Inverse of Speed Ratio
If Speed A : B = a : b,
then Time A : B = b : a
Time ratio = 5 : 3
A head start means one runner is allowed to start ahead of another runner by a certain distance.
B runs only (D − x) metres.
A's time = 100/10 = 10 s
B's distance = 100 − 20 = 80 m
B's time = 80/8 = 10 s
Hence, both reach the finish line at the same time.
If A can give B a head start of x metres in a race of D metres, then:
A : B = 100 : 75
= 4 : 3
Sometimes the winner finishes a race a certain number of seconds before the other runner.
Time difference = 25 − 20
= 5 seconds
Therefore, A wins by 5 seconds.
Suppose both runners start together. A completes D metres while B completes only D − x metres in the time A takes.
Speed B = (D − x)/t
Therefore:
Speed A : Speed B = D : (D − x)
If B takes y seconds more than A, then:
If the same two runners participate in races of different lengths, calculate the time using:
| Given Information | Useful Relation |
|---|---|
| A beats B by x metres in D metres | Speed ratio = D : (D − x) |
| Speed ratio a:b | Same-time distance ratio = a:b |
| Equal distance | Time ratio = inverse speed ratio |
| Head start x in D race | Runner covers D − x |
In a circular race, runners move around a circular track. The important concept is relative speed.
Relative Speed in Same Direction = |S₁ − S₂|
Relative speed = 8 + 6 = 14 m/s
Time = 400/14
= 28.57 seconds approximately
If two runners start together from the same point and run in the same direction, the faster runner catches the slower runner after covering one complete extra round relative to the slower runner.
Relative speed = 10 − 7 = 3 m/s
Catch-up time = 600/3
= 200 seconds
In aptitude questions, a game of skill generally describes a competition between two players where their scores, points, goals, runs or performances are compared.
The mathematical approach is usually based on ratios, differences, percentages and proportional relationships.
Total Score = Score of Player A + Score of Player B
A : B = 60 : 45
= 4 : 3
A's score = T × a/(a+b)
B's score = T × b/(a+b)
Total parts = 5 + 3 = 8
A = 64 × 5/8 = 40
B = 64 × 3/8 = 24
If each game gives a fixed number of points, total points can be calculated from the number of games won or lost.
| Concept | Formula / Relation |
|---|---|
| Basic Speed | Speed = Distance ÷ Time |
| Race Margin | A beats B by x in D race → A:B = D:(D−x) |
| Same-Time Distance | Distance ratio = Speed ratio |
| Same-Distance Time | Time ratio = Inverse speed ratio |
| Head Start | Runner with x m start covers D−x |
| Opposite Circular Race | Meeting time = Track length ÷ (S₁+S₂) |
| Same-Direction Circular Race | Catch-up time = Track length ÷ |S₁−S₂| |
| Score Ratio | If A:B=a:b, A=T×a/(a+b) |
A : B = 150 : 120
= 5 : 4
A's time = 120/12 = 10 s
B's distance = 120 − 40 = 80 m
B's time = 80/8 = 10 s
Therefore, they finish together.
Total parts = 12
First score = 144 × 7/12 = 84
Second score = 144 × 5/12 = 60
``` 1. 5 : 4
2. 400 m
3. Yes, both take 10 seconds
4. 5 : 4
5. 50 seconds
6. 200 seconds
7. A = 60, B = 40
8. 5 seconds
9. 300 m
10. 24 points ```
``` 2. Same time → distance is directly proportional to speed.
3. "A beats B by x metres in D metres" → use D : (D−x).
4. Circular track + opposite direction → add speeds.
5. Circular track + same direction → subtract speeds.
6. For score problems, convert ratios into total parts first.
7. Always keep distance and speed in compatible units before calculating time. ```